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. We initially clearly show that x mod n = a mod n. It's generally accurate that (a + bn) mod n = a mod n for all integers b; thus, This is certainly correct also in the particular circumstance when b = − ⌊ a − d n ⌋ textstyle b=-!remaininglfloor frac a-d n correctrfloor What We Don’t Like: The once-a-year rate is $95. There’s also a si